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-.06x^2+1.5x+6=0
We add all the numbers together, and all the variables
-0.06x^2+1.5x+6=0
a = -0.06; b = 1.5; c = +6;
Δ = b2-4ac
Δ = 1.52-4·(-0.06)·6
Δ = 3.69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.5)-\sqrt{3.69}}{2*-0.06}=\frac{-1.5-\sqrt{3.69}}{-0.12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.5)+\sqrt{3.69}}{2*-0.06}=\frac{-1.5+\sqrt{3.69}}{-0.12} $
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